15/03/2009, 01:26 PM
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محظور
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تاريخ الانضمام: 30/11/2008
الإقامة: في قلبها من بعد برج الصحوة
الجنس: ذكر
المشاركات: 921
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اقتباس:
أرسل أصلا بواسطة غدار الليل
يلا يا شباب
قررت انزل الحل قبل انتهاء الاسبوع
متى 1+1=3
Way’s to ‘prove’ 1+1 = 3:
PROOF #001
A. X = X, Y = Y, X + 0 = X, Y + 0 = Y (Identity)
B. Y + (-Y) = 0 (Additive Inverse)
C. X/X = 1 (Multiplicative Inverse)
STEP 1, PROVE 1 = 0
Eq 1 ==> let X = Y
Eq 2 ==> since X + 0 = X
then, replacing X with X + 0, we have X + 0 = Y
Eq 3 ==> then, X + [Y+(-Y)] = Y
Eq 4 ==> then, X + Y - Y = Y
Eq 5 ==> then, (X - Y) + Y = Y
Eq 6 ==> then, (1/X - Y)[(X - Y) + Y] = Y (1/X - Y)
Eq 7 ==> then, [(X - Y)/(X - Y)] + [Y/(X - Y)] = Y/(X - Y)
Eq 7 ==> then, 1 + [Y/(X - Y)] =[ Y/(X - Y)]
Eq 8 ==> then, 1 = [Y/(X - Y)] - [Y/(X - Y)]
Eq 9 therefore, 1 = 0
STEP 2, PROVE 1+1=3
since 1=1 (identity property), and 1=0 (from eq 9)
Using Algebraic sum, add the following equations:
Eq (a) 1=1 (identity)
Eq (b) 1=1 (identity)
Eq (c) 0=1 (fr, Eq 9)
1 + 1 + 0 = 1 + 1 + 1
Therefore, 1+ 1 = 3 :-p
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The lines in red are totaly wrong
you cannot divide on ZERO !
since X=Y, then X-Y = Zero
Your solution is a mess
You are wrong
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